7x^2+8x-11=0

Solution for 7x^2+8x-11=0 equation:

7x^2+8x-11=0

a = 7; b = 8; c = -11;
Δ = b2-4ac
Δ = 82-4·7·(-11)
Δ = 372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{372}=\sqrt{4*93}=\sqrt{4}*\sqrt{93}=2\sqrt{93}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{93}}{2*7}=\frac{-8-2\sqrt{93}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{93}}{2*7}=\frac{-8+2\sqrt{93}}{14}
$